Schoolwork Help Thread

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AWA Offline
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Schoolwork Help Thread

Posted: Mon Jul 19, 2010 11:00 am



Come here for help with schoolwork. Try to refrain from outright cheating.

-----

Does anyone know how I can apply the differentiation rules to physics formulae? In particular, instantaneous velocity/acceleration.
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ottomagne Offline
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Re: Schoolwork Help Thread

Posted: Mon Jul 19, 2010 11:04 am



Acceleration is the integration of velocity with respect to time. Thus, differentiating acceleration at a given point would give the the velocity at that point in time. Is that what you were asking about?
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AWA Offline
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Re: Schoolwork Help Thread

Posted: Mon Jul 19, 2010 11:06 am



No, I was wondering how I could apply the rules (Power Rule, Chain Rule, etc.) to the a=dv/dt equation. I figured it out though, turns out I'm just really dumb.
2007 - 2010: West Deptford High School (07-08 FE, 09-10 quads)
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ottomagne Offline
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Re: Schoolwork Help Thread

Posted: Mon Jul 19, 2010 11:09 am



Ahh okay hahaha.

I always found it exciting to figure out what happens when you differentiate/integrate physics equations. I wish my school offered Physics C - I think I actually would have fared better on that test then the Physics B one.
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Re: Schoolwork Help Thread

Posted: Wed Jul 21, 2010 8:03 pm



This may be a bit early for schoolwork....


Hertaz Offline
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Re: Schoolwork Help Thread

Posted: Sun Sep 12, 2010 7:30 pm



Okay, so a police car is sitting on the road at rest. A speeding car going 92 km/h. When the speeding car is 250 m behind the police car, the police car begins to accelerate. How fast does the police car need to accelerate in order to be going the same speed as the speeding car when it passes the policemen?

This question is screwing with my mind.

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Re: Schoolwork Help Thread

Posted: Sun Sep 12, 2010 8:42 pm



Let the police car be sitting at the origin of an inertial reference frame.
Let the time the car passes the policeman = t = n seconds.

V = 92 km/h = 25.56 m/s

A = dV/dt
A = 25.56/n

dxcar = Vot + .5a(t^2)
dxcar = 25.56n

dxpolice = Vot + .5a(t^2)
dxpolice = .5(25.56/n)(n^2)
dxpolice = 12.78n

dxcar = dxpolice +250
25.56n = 12.78n +250
12.78n = 250
n = 19.56s

A = 25.56/19.56
A = 1.31 m/s^2
2007 - 2010: West Deptford High School (07-08 FE, 09-10 quads)
2013: Spirit of Atlanta (Marimba)
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Hertaz Offline
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Re: Schoolwork Help Thread

Posted: Sun Sep 12, 2010 8:43 pm



God you are amazing. Thank you.
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LilPurpQuads wrote:I mean NOW at the beginning of the season they're dirty, but when it gets closer to mid and finals... They somehow happen to be good?


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Re: Schoolwork Help Thread

Posted: Sun Sep 12, 2010 8:46 pm



AWA wrote: Try to refrain from outright cheating.
how is doing the problem for him NOT outright cheating?
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Re: Schoolwork Help Thread

Posted: Sun Sep 12, 2010 8:48 pm



hotbeats645 wrote:
AWA wrote: Try to refrain from outright cheating.
how is doing the problem for him NOT outright cheating?
He showed HOW to do it.
This is a turtle:

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AWA Offline
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Re: Schoolwork Help Thread

Posted: Sun Sep 12, 2010 8:50 pm



Captain_Pit wrote:
hotbeats645 wrote:
AWA wrote: Try to refrain from outright cheating.
how is doing the problem for him NOT outright cheating?
He showed HOW to do it.
Correct. "Cheating" would be... "I've got a test, here are the questions, give me the answers."

Here I've walked him through the process, using a single question as a frame to teach the concept.

It would be cheating if I said:

A = 1.31 m/s^2
2007 - 2010: West Deptford High School (07-08 FE, 09-10 quads)
2013: Spirit of Atlanta (Marimba)
2014: Bluecoats (Vibraphone)

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Hertaz Offline
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Re: Schoolwork Help Thread

Posted: Sun Sep 12, 2010 9:44 pm



And it's not a graded homework. I guess it would have sounded more legit if I had mentioned that.
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LilPurpQuads wrote:I mean NOW at the beginning of the season they're dirty, but when it gets closer to mid and finals... They somehow happen to be good?


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Re: Schoolwork Help Thread

Posted: Sun Sep 12, 2010 10:09 pm



i'm more of a fan of explaining the process/helping out by supplying some formulas instead of doing the problem for somebody and hoping they'll apply what they learned to other problems.

if you're going to walk through the process using a single question as a frame to teach the concept and the person only asked for help on one problem, it's not really a help thread, IMO.

I'm glad you got it though, and it's all cool, I was just pointing that out.
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Hertaz Offline
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Re: Schoolwork Help Thread

Posted: Sun Sep 12, 2010 10:35 pm



I know the formulae, I was just having trouble understanding how to apply it. Our physics teacher always gives us the answers to our homework when he assigns it so we know we did it correctly. When I used one formula, I got 2.6. When I did another formula, I got .65. I didn't understand how I was always twice or half that correct answer. I probably should have mentioned that earlier so as to avoid confusion. Now you know.
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LilPurpQuads wrote:I mean NOW at the beginning of the season they're dirty, but when it gets closer to mid and finals... They somehow happen to be good?


AWA Offline
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Re: Schoolwork Help Thread

Posted: Mon Sep 13, 2010 1:24 pm



Just remember:

The formulae aren't the be-all-end-all of solution mechanisms. Don't forget regular algebra.
2007 - 2010: West Deptford High School (07-08 FE, 09-10 quads)
2013: Spirit of Atlanta (Marimba)
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Re: Schoolwork Help Thread

Posted: Mon Sep 13, 2010 6:54 pm



thats true, i remember in physics last year a lot of the time my partner got something wrong, she just did the algebra wrong
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I work in music tech and licensing.

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Re: Schoolwork Help Thread

Posted: Mon Sep 13, 2010 7:20 pm



I know the final answer is just x, but I'm at a loss of how to get there.
I know this is also a step, but I'm not seeing how to get it either.
((5x)/(x-1)) / ((5)/(x-1))

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AWA Offline
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Re: Schoolwork Help Thread

Posted: Mon Sep 13, 2010 8:03 pm



You need to create a single denominator on both parts of the fraction.

Use cross-cross-together:

a/b + c/d = (ad + bc)/(bd)

Top:

(2x+3)/(x-1) + 3 = (2x +3 +3x -3)/(x-1) = 5x/(x-1)

Bottom:

(2x+3)/(x-1) - 2 = (2x + 3 - 2x + 2)/(x-1) = 5/(x-1)

Thus, the entire fraction is:

(5x/(x-1))/(5/(x-1))

Division of a fraction:

(a/b)/(c/d) = ad/bc

((5x)(x-1))/((5)(x-1))

Cancel "(x-1)"

5x/5

Cancel 5

x
2007 - 2010: West Deptford High School (07-08 FE, 09-10 quads)
2013: Spirit of Atlanta (Marimba)
2014: Bluecoats (Vibraphone)

-Glenn Dawson

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Wx3141 Offline
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Re: Schoolwork Help Thread

Posted: Mon Sep 13, 2010 8:12 pm



AWA wrote:You need to create a single denominator on both parts of the fraction.

Use cross-cross-together:

a/b + c/d = (ad + bc)/(bd)
[. . .]
Cancel "(x-1)"

5x/5

Cancel 5

x
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AWA Offline
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Re: Schoolwork Help Thread

Posted: Tue Sep 14, 2010 8:03 pm



Wx3141 wrote:
AWA wrote:You need to create a single denominator on both parts of the fraction.

Use cross-cross-together:

a/b + c/d = (ad + bc)/(bd)
[. . .]
Cancel "(x-1)"

5x/5

Cancel 5

x
You are a saint. <3
Cross-cross-together is like the single most useful equation out there, except maybe the Pythagorean theorem.
2007 - 2010: West Deptford High School (07-08 FE, 09-10 quads)
2013: Spirit of Atlanta (Marimba)
2014: Bluecoats (Vibraphone)

-Glenn Dawson

"Pedicabo ego vos et irrumabo."


Wx3141 Offline
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Re: Schoolwork Help Thread

Posted: Tue Sep 14, 2010 8:15 pm



AWA wrote:Cross-cross-together is like the single most useful equation out there, except maybe the Pythagorean theorem.
I asked my pre-cal teacher about it today because that basically helped me on half of those questions.
She said, "Because if your past teachers had told you that equation a long time ago, the lesson would've been over way too early."
I just facepalm'd.


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Re: Schoolwork Help Thread

Posted: Sun Sep 19, 2010 7:41 pm



Does anyone know what a janitor does instead of cleaning? I have to do an essay on a job I would not like to have.


Hertaz Offline
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Re: Schoolwork Help Thread

Posted: Sun Sep 19, 2010 8:58 pm



kiddrummer wrote:Does anyone know what a janitor does instead of cleaning? I have to do an essay on a job I would not like to have.

Maintains equipment, repairs broken learning tools, etc etc. Janitors are like cleaning ladies, mechanics, electricians, and engineers all in one.
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PSUid Drumset 2013

For the glory.
LilPurpQuads wrote:I mean NOW at the beginning of the season they're dirty, but when it gets closer to mid and finals... They somehow happen to be good?


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Re: Schoolwork Help Thread

Posted: Sun Nov 28, 2010 6:54 pm



Ugh, I hope this gets checked tonight, and that someone can help me. It's embarrassing that I even have to ask about this, I've learned how to do this in the 9th grade, and again a couple weeks ago. Now I'm trying to review for a quiz and I can't remember how to solve a system of equations with three variables in them. The ones that have 3 of the at least one variable that exists in all three equations, I have figured out.

EX:

x+y+z=6
2x-y+z=3
3x-z=0

I figured out how to do this one, because I could eliminate the X variable, as it is present in all three equations. However, a few of the systems of equations don't have this.

EX:

2x+2z=2
5x+3y=4
3y-4z+4


The textbook says the solution should be (-4,8,5). How do you get this answer? I know it's something really simple, but I can't remember how to do it.


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Re: Schoolwork Help Thread

Posted: Sun Nov 28, 2010 8:11 pm



noname wrote: 2x+2z=2
5x+3y=4
3y-4z=4
The textbook says the solution should be (-4,8,5). How do you get this answer? I know it's something really simple, but I can't remember how to do it.
I tried. Looks like it requires a matrix.

EDIT: This nifty little thing works excellently. It will teach you how to do it.
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